Answer:
[tex](0,20),(1,16),(2,12)[/tex]
Step-by-step explanation:
[tex]We\ are\ provided\ with\ the\ equation:\\4x+y=20\\In\ order,\ to\ find\ solutions\ to\ a\ linear\ equation\ in\ two\ variables,\ we\\ usually\ substitute\ a\ value\ to\ either\ the\ abscissa or\ the\ ordinate\ to\ get\\ the\ corresponding\ ordinate\ or\ the\ abscissa.\\Hence,\\Here,[/tex]
[tex]Let's\ plug\ in\ simpler\ value's\ of\ 0,1,2\ as\ the\ x-co-ordinate\ to\ obtain\ it's\\ y-coordinate.\\Hence,\\Coming\ back\ to\ our\ equation:4x+y=20\\Substituting\ x=0,\\4*(0)+y=20\\y=20\\Hence,\\x=0,y=20\ or\ (0,20)\ is\ a\ solution\ of\ the\ equation.[/tex]
[tex]Substituting\ x=1,\\4*(1)+y=20\\4+y=20\\y=20-4=16\\Hence,\\x=1,y=16\ or\ (1,16)\ is\ also\ a\ solution\ of\ the\ equation.[/tex]
[tex]Substituting\ x=2,\\4*(2)+y=20\\8+y=20\\y=20-8=12\\ Hence,\\x=2,y=12\ or\ (2,12)\ is\ a\ solution\ of\ the\ equation\ too.[/tex]
[tex]Hence,\ collecting\ all\ the\ solutions\ of\ the\ equations:\\(0,20),(1,16),(2,12)\ are\ all\ solutions\ of\ the\ given\ equation.\\[/tex]
