Answer:
the second option
Step-by-step explanation:
[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]
[tex] \cos(theta) = \frac{adjacent}{hypotenuse} [/tex]
[tex] \tan(theta) = \frac{opposite}{adjacent} [/tex]
theta = 45°
hypotenuse = 9
opposite = x
find x using the sin formula
[tex] \sin(theta) = \frac{opposite}{hypotenuse} [/tex]
[tex] \sin(45) = \frac{x}{9} [/tex]
[tex] \sin(45) \times 9 = x[/tex]
[tex] \frac{9 \sqrt{2} }{2} = x[/tex]
[tex]x = \frac{9 \sqrt{2} }{2} [/tex]
