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Suppose the driver of a vehicle applies the brakes while traveling at 8.25 m/s and the car stops after
traveling 24.0 m. What was the car's acceleration?

Answer :

ChoiSungHyungo

Explanation:

u = 8.25m/s

v = 0.00m/s

s = 24.0m

Using Kinematics, we have v² = u² + 2as.

=> a = (v² - u²) / 2s

= [(0)² - (8.25)²] / 2(24) = -1.42m/s². (3s.f.)

Lizr40203go

Answer:

15.96

Explanation:

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