Answer:
The speed of the ball in terms of i and j is (15.76 i, 6.37 j)
Step-by-step explanation:
Given;
velocity of the ball, v = 17 mph
angle of inclination, θ = 22⁰
The horizontal component of the velocity is calculated as;
[tex]V_x = Vcos\theta\\\\V_x = 17cos(22)\\\\V_x = 15.76 \ i[/tex]
The vertical component of the velocity is calculated as;
[tex]V_y = Vsin\theta\\\\V_y = 17sin(22)\\\\V_y = 6.37 \ j[/tex]
Therefore, the speed of the ball in terms of i and j is (15.76 i, 6.37 j)
