👤
Answered

A system of equations is given below.

{
5
x
−
2
y
=
3
3
x
−
y
=
4
{
5x−2y=3 3x−y=4⁢
Which of these procedures will eliminate a variable in one of the equations in the system above?
A.
Multiply the second equation by –2 then add the result to the first equation.
B.
Multiply the second equation by 2 then add the result to the first equation.
C.
Multiply the first equation by –2 then add the result to the second equation.
D.
Multiply the first equation by 2 then add the result to the second equation.

Answer :

The anwser is A

By multiplying the second equation by -2, it makes the new equation -6x+2y = -8

When you add that to the first equation you get x=-5

Go Teaching: Other Questions