Answer:
[tex]m_{NaCl}=19.9gNaCl[/tex]
Explanation:
Hello!
In this case, since the formula for the calculation of molarity is:
[tex]M=\frac{n}{V}[/tex]
Whereas we can compute the moles of the solute as shown below, making sure the volume is in liters:
[tex]n=M*V[/tex]
Thus, by plugging in we obtain:
[tex]n=0.200L*1.70mol/L=0.170molNaCl[/tex]
Next, since the molar mass of NaCl is 58.44 g/mol, we obtain the following mass:
[tex]m_{NaCl}=0.170molNaCl*\frac{58.44gNaCl}{1molNaCl}\\\\m_{NaCl}=19.9gNaCl[/tex]
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