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Answer :

LadyStrangego

Let the red cat be represented by x.

Let the yellow cat be represented by y.

Let the white cat be represented by z.

Which means :

[tex] \tt (1) \: \frac{4}{5} (20x - 5)[/tex]

[tex]\tt = \frac{4}{5} \times 20x - \frac {4 }{5} \times 5[/tex]

[tex] \tt= \frac{80x}{5} - \frac{20}{5} [/tex]

[tex]\tt = 16x - 14[/tex]

Thus, the first statement is correct.

[tex]\tt(2) \: \frac{3}{5} ( \frac{1}{3} z - 10)[/tex]

[tex]\tt = \frac{3}{5} \times \frac{1}{3} z - \frac{3}{5} \times 10[/tex]

[tex]\tt = \frac{3}{15} z- \frac{30}{5} [/tex]

[tex]\tt = \frac{1}{5} z - 6[/tex]

Thus, the second statement is a lie.

[tex]\tt(3) \: \frac{1}{9} ( - 9y - 27x)[/tex]

[tex] \tt= \frac{1}{9} \times - 9y - \frac{1}{9} \times 27x[/tex]

[tex]\tt = \frac{ - 9}{ \: \: 9} y - \frac{27}{9} x[/tex]

[tex]\tt = (- y) - 3x[/tex]

Thus, the third statement is correct.

Therefore, the second one is a lie.

ItzDevilKinggo

Answer:

Let the money with Miguel be x.

Then :

Money with Kira = x - 9

Money with Charlie = 4x

Total money in their wallet = $105

This can be written in an equation as :

= \tt \: x + x - 9 + 4x = 105=x+x−9+4x=105

= \tt2x + 4x - 9 = 105=2x+4x−9=105

= \tt 6x - 9 = 105=6x−9=105

= \tt6x = 105 + 9=6x=105+9

= \tt6x = 114=6x=114

= \tt x = \frac{114}{6}=x=

6

114

= \tt x = 19=x=19

Which means :

Money with Miguel = $19

Money with Kira :

= 19 - 9

Thus, Kira has $10 in her wallet.

Money with Charlie :

= 4 × 19

= 76

Thus, Charlie has $76 in his wallet.

Therefore,

Money with Kira = $10

Money with Charlie = $76

Money with Miguel = $19

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