Answer:
b= (2a+11)/5
Step-by-step explanation:
5x + 2y = 9
2y=9-5x
y= 9/2 - 5x/2
slope, m1= -5/2
for perpendicularity, m1 × m2 = -1
slope for QR= m2=
[tex] = - 1 \div \frac{ - 5}{2} = - 1 \times \frac{2}{ - 5} = \frac{ - 2}{ - 5} = \frac{2}{5} [/tex]
m2 is 2/5
[tex]qr = \frac{b - 3}{a - 2} [/tex]
[tex] \frac{2}{5} = \frac{b - 3}{a - 2} [/tex]
5(b-3)=2(a-2)
5b-15=2a-4
5b=2a-4+15
5b= 2a+11
[tex]b = \frac{2a + 11}{5} [/tex]
