Answer:
v=-5 and v=3
Step-by-step explanation:
We are given that
[tex]v^2-15=-2v[/tex]
We have to find two solutions of quadratic equation.
[tex]v^2+2v-15=0[/tex]
Using addition property of equality
[tex]v^2+5v-3v-15=0[/tex] (By using factorization method)
[tex]v(v+5)-3(v+5)=0[/tex]
[tex](v+5)(v-3)=0[/tex]
Substitute each factor equal to 0
[tex]v+5=0[/tex] and [tex]v-3=0[/tex]
[tex]v=-5[/tex] and [tex]v=3[/tex]
Hence, two solutions of quadratic equation are
v=-5 and v=3
