Answer:
[tex]\bold{104u^2+65v^2+5w^2-16uv+40uw-14vw}[/tex]
Step-by-step explanation:
Perimeter of the triangle is the sum of its side lengths.
[tex](2u-4v)(2u-4v)+ (10u+2w)(10u+2w)+ (w-7v)(w-7v)=\\\\= (2u)^2-2\cdot2u\cdot4v+(4v)^2\ +\ (10u)^2+2\cdot10u\cdot2w+(2w)^2\ +\ \\\\{}\qquad\qquad\qquad \qquad\qquad\qquad\qquad\qquad\quad +w^2-2\cdot w\cdot7v+(7v)^2=\\\\=4u^2-16uv+16v^2+100u^2+40uw+4w^2+w^2-14wv+49v^2 =\\\\=104u^2+65v^2+5w^2-16uv+40uw-14vw[/tex]
