The cubic inches that can fill the cylinder is [tex]112\pi[/tex] and the decimal approximation 351.68 cm^3
The given parameters are:
Radius (r) = 4 cm
Height (h) = 7 cm
The area of the base
The area of the base is:
[tex]A = \pi r^2[/tex]
So, we have:
[tex]A = \pi *4^2[/tex]
[tex]A = 16\pi[/tex]
Hence, the area of the base is [tex]16\pi[/tex]
The cubic inches that can fill the cylinder
This is the volume of the cylinder.
So, we have:
[tex]V = \pi r^2h[/tex]
Substitute known values
[tex]V = \pi * 4^2 * 7[/tex]
[tex]V = 112\pi[/tex]
Hence, the cubic inches that can fill the cylinder is [tex]112\pi[/tex]
The decimal approximation
We have:
[tex]V = 112\pi[/tex]
Expand
[tex]V = 112 * 3.14[/tex]
Evaluate the product
[tex]V = 351.68[/tex]
Hence, the cubic inches that can fill the cylinder is 351.68 cm^3
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