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Physics

Answered

A spring measuring 20cm is stretched by a force of ION and becomes
22cm long, What is the k-constant of this spring?

Answer :

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Answer:

500N/m

Explanation:

Original Length = 20cm

Final length = 22cm

extension = 22 - 20 = 2cm = 0.02m

Force F = 10N

From Hooke's law, F = ke

==> k = F/e = 10/0.02 = 500N/m

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