Answer:
1.34 * 10^-7 M
Explanation:
The Ksp of lead II chromate is 1.8 x 10^-14
So, we have that;
PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)
s s
Where s = molar concentration of Pb^2+(aq) and CrO4^2-(aq)
and;
[Pb^2+] = [CrO4^2-]
This implies that Ksp = s^2
s = √Ksp
s = √1.8 x 10^-14
s = 1.34 * 10^-7 M
