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Answer :

Answer:

C. {-9,-3}

Step-by-step explanation:

[tex]|k+6|=3[/tex] gives [tex]k+6=3[/tex] if [tex]k + 6 \geq 0[/tex]. This gives [tex]k=-3[/tex], which is valid.

It can also give [tex]-(k+6) = 3[/tex] if [tex]k + 6 < 0[/tex]. This gives [tex]k=-9[/tex], which is valid.

Hence the solutions are [tex]k=-9 \vee k=-3[/tex].