Answer:
the time of motion of the ball is 6.89 ms.
Explanation:
Given;
angular speed, ω = 38 rad/s
angular distance, θ = 15 degrees
Angular distance in radian;
[tex]\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad[/tex]
Time of motion is calculated as;
[tex]time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms[/tex]
Therefore, the time of motion of the ball is 6.89 ms.
