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A motorist is driving at a constant velocity of 28.0 m/s when he decides to pass a car is in front of him. He accelerates at a rate 2.50 m/s2 for 3.00 seconds while passing the car. What is his velocity at the end of the 3.00 seconds?

Answer :

Lanuelgo

Answer:

Final velocity, V = 35.5m/s

Explanation:

Given the following data;

Initial velocity = 28m/s

Acceleration = 2.5m/s²

Time = 3 seconds

To find the final velocity, we would use the first equation of motion

V = U + at

Where;

V is the final velocity measured in m/s.

U is the initial velocity measured in m/s.

a is the acceleration measured in m/s².

t is the time measured in seconds.

Substituting into the equation, we have;

V = 28 + 2.5*3

V = 28 + 7.5

Final velocity, V = 35.5m/s

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