Answer:
The solution is (0,4).
Step-by-step explanation:
We are given the following system of equations:
[tex]8x + 9y = 36[/tex]
[tex]3x + 4y = 16[/tex]
Solving by substitution.
In the first equation, we have that:
[tex]8x + 9y = 36[/tex]
[tex]8x = 36 - 9y[/tex]
[tex]x = \frac{36-9y}{8}[/tex]
Replacing in the second equation:
[tex]3x + 4y = 16[/tex]
[tex]3\frac{36-9y}{8} + 4y = 16[/tex]
Multiplying everything by 7
[tex]3(36 - 9y) + 32y = 128[/tex]
[tex]108 - 27y + 32y = 128[/tex]
[tex]5y = 20[/tex]
[tex]y = \frac{20}{5}[/tex]
[tex]y = 4[/tex]
Now, with y, we can find x.
[tex]x = \frac{36-9*4}{8} = 0[/tex]
So the solution is (0,4).
