Answer:conjectured that F(n)≈0.72∗n∗f(n). Following that clue, we can find the following identity holds for all cases we tested by trial and error.
F(n)=nf(n)−(n−2)f(n−2)+(n−4)f(n−4)−(n−6)f(n−6)+⋯
where the sequence of summands goes on as long as the summand makes sense.
Step-by-step explanation:
