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Answer :

Spacego

Answer:

62.1 g Al

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

2.30 mol Al

Step 2: Identify Conversions

[PT] Molar Mass of Al - 26.98 g/mol

Step 3: Convert

  1. Set up:                              [tex]\displaystyle 2.30 \ mol \ Al(\frac{26.98 \ g \ Al}{1 \ mol \ Al})[/tex]
  2. Multiply/Divide:                [tex]\displaystyle 62.054 \ g \ Al[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

62.054 g Al ≈ 62.1 g Al

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