Answer:
23.6 m
Explanation:
We are given that
Mass of ball, m=7.0 kg
Force, F=810 N
Distance, s=2.0 m
We have to find the height of ball from the point where it releases.
Work done=K.E
[tex]Fs=\frac{1}{2}mv^2[/tex]
[tex]v^2=\frac{2Fs}{m}[/tex]
Substitute the value
[tex]v^2=\frac{2\times 810\times 2}{7}[/tex]
[tex]v^2=\frac{3240}{7}[/tex]
K.E=P.E
[tex]\frac{1}{2}mv^2=mgh[/tex]
[tex]\frac{1}{2}v^2=gh[/tex]
Where g=[tex]9.8m/s^2[/tex]
[tex]\frac{1}{2}\times \frac{3240}{7}=9.8h[/tex]
[tex]h=\frac{3240}{7\times 2\times 9.8}[/tex]
[tex]h=23.6 m[/tex]
