Helpppp! This assignment is due in 15 minutes . Click the photo attached.

Answer:
1: 6.637e-13 N
2: 6.637e-09 N
3: 1.335e-08 N
4: 1.335e-08 N
5: 1.456e-06 N
6: 5.839e-07 N
7: 6.673e-11 N
I'd suggest double checking these if you can.
Explanation:
Each of these you can answer by plugging the numbers into the equation
[tex]F = G\frac{m_1 m_2}{r^2}[/tex]
G is the gravitational constant 6.673×10⁻¹¹ N m² / kg²
So the first one would be:
[tex]F = 6.673 \times 10^{-11} \frac{Nm^2}{kg^2} \times\frac{1kg\times 1kg}{(10m)^2}\\F = 6.673 \times 10^{-11} N \times\frac{1}{100}\\F = 6.673 \times 10^{-13}N[/tex]
I'm not going to run through showing all calculations for the rest, as you're in a rush, so to whip through them
2: 6.637e-09 N
3: 1.335e-08 N
4: 1.335e-08 N
5: 1.456e-06 N
6: 5.839e-07 N
7: 6.673e-11
Pardon the lack of superscript, I just punched these into a python console to calculate them.