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Answer :

ItzShinyQueen13go

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]

[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find :- }}[/tex]

[tex] \sf• \: The \: Resistance. [/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution :- }}[/tex]

[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]

[tex] \rightarrow \sf R = \frac{9}{18} [/tex]

[tex] \rightarrow \sf R = \frac{1}{2}[/tex]

[tex] \rightarrow \sf R = 0.5[/tex]

[tex] \\ [/tex]

[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]

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