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When iron rusts in the presence of oxygen, iron (III) oxide is produced. How many moles
of oxygen react with 9.8 moles of iron in the rusting reaction?

Answer :

Answer: 7.35 moles O2

Explanation:

4Fe + 3O2 —> 2Fe2O3

if 9.8 moles Fe, 3/4 moles O2 = 7.35

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