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Write an equation of the line that is perpendicular to the given line and that passes through the given point.
y = −4x + 2; (−4, −3)

Answer :

Kmvisgo
The equation would be y+3=(1/4)(x+3)
Gradient of the perpendicular line is the negative reciprocal of the original line.
So the gradient is 1/4
Therefore
y-(-3)=(1/4)(x-(-4))
y=(1/4)x-2

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