Answer :
Answer:
The x-intercepts of the function are 0 and 6, which are a lower bound and an upper bound for the possible values of the width of the storage bin.
Step-by-step explanation:
Given
[tex]A(x) = x^2 - 6x[/tex]
Required
Which is true about the x intercept
To do this, we make A(x) = 0.
Substitute 0 for A(x) in [tex]A(x) = x^2 - 6x[/tex]
[tex]0 = x^2 - 6x[/tex]
Rewrite as:
[tex]x^2 - 6x=0[/tex]
Factorize:
[tex]x(x - 6)=0[/tex]
Split:
[tex]x = 0\ or\ x - 6 = 0[/tex]
[tex]x = 0\ or\ x = 6[/tex]
Option D is correct