Answer:
411.88 N
Explanation:
Given that:
mass of satellite m = 1847 kg
mass of the earth M = 5.97 × 10²⁴ kg
centripetal acceleration a = 0.223 m/s²
The magnitude of the force exerted by the earth on the satellite = the centripetal force that is being exerted by the satellite.
∴
[tex]m \dfrac{v^2}{r} = G \dfrac{mM}{r^2}[/tex]
[tex]ma = G \dfrac{mM}{r^2}[/tex]
[tex]G \dfrac{mM}{r^2}= 1847 \times 0.223[/tex]
[tex]G \dfrac{mM}{r^2}= 411.88 \ N[/tex]
