Find the 8th term of the geometric sequence 3, 12, 48, ....

Answer:
The eighth term of the geometric sequence 3, 12, 48 ... is 49,152. You just multiply every number by 4 :)
So, the required 8th term is 49152.
The Geometric series formula or the geometric sequence formula gives the sum of a finite geometric sequence.
The sequence will be of the form [tex]\{a, ar, ar^2, ar^3, ..\}[/tex]
And the formula for the nth term is [tex]t_n=ar^{n-1}[/tex]
The given series is,
3, 12, 48, ....
First term=3
The common ratio is,
[tex]\frac{12}{3}=4\\ \frac{48}{12}=4[/tex]
So, the given series is geometric series so the 8th term by the above formula is,
[tex]t_8=3\times (4)^{8-1}\\t_8=49152[/tex]
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