Answer :
Answer: 0.614
Step-by-step explanation:
First find the probability that he catches the bus in a day.
Probability of catching bus once = 1 - Probability of missing bus
= 1 - 0.15
= 0.85
If he arrives on 3 consecutive days at 7:30 am, the probability he will catch the bus is:
= (P | Day 1) * (P | Day 2) * (P | Day 3)
= 0.85 * 0.85 * 0.85
= 0.614
The approximate probability that he catches the bus all three days is 0.614.
Given that,
Forrest has determined that if he gets to the bus stop at 7:30 am, there is a 0.15 probability that he misses the bus.
If he arrives at the bus stop three consecutive days at 7:30,
We have to determine,
What is the approximate probability that he catches the bus all three days.
According to the question,
The probability that he catches the bus in a day.
Probability of catching bus once = 1 - Probability of missing bus,
= 1 - 0.15
= 0.85
If he arrives on 3 consecutive days at 7:30 am,
Then, the probability he will catch the bus is:
= (P | Day 1) × (P | Day 2) × (P | Day 3)
= 0.85 × 0.85 × 0.85
= 0.614
Hence, The approximate probability that he catches the bus all three days is 0.614.
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