Answer :
Answer:
0.03 M
Explanation:
The computation of the molarity of the diluted HCI is given below:
As we know that
(M1) × (V1) = (M2) × (V2)
Now
(M2) = {(M1) × (V1)} ÷ (V2)
or
Molarity of the diluted HCl,(M2) is
= {6 × 25} ÷ 5000
= 0.03 M
Answer:
0.03 M
Explanation:
The computation of the molarity of the diluted HCI is given below:
As we know that
(M1) × (V1) = (M2) × (V2)
Now
(M2) = {(M1) × (V1)} ÷ (V2)
or
Molarity of the diluted HCl,(M2) is
= {6 × 25} ÷ 5000
= 0.03 M