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Moharoobiigo
Answered

An arrow thrown with a 45° reaches a maximum height of 12 m. Find its initial velocity.

235m/s

15.3m/s

22m/s

17m/s




Answer and I will give you brainiliest

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Answer :

Dammyzeego

Answer:

17m/s

Step by step explanation:

Using g= 10m/s²

Maximum H = (u²sin²theta) /2g

12 = u² sin²(45)/2(10)

12 = u²(0.72)/20

0.72 u²= 240

u² = 240/0.72 = 333.33

Initial velocity = 18.3m/s

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