Answer :
Answer:
h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,
if its asking for:
[tex]\int\limits^2_7 {16t} \, dt[/tex]
then it's
16(2) - 16(7) = 32 - 112 = -80
Answer:
h(t) = 16t changes 16 units every t. in the interval t=7 to t=2,
if its asking for:
[tex]\int\limits^2_7 {16t} \, dt[/tex]
then it's
16(2) - 16(7) = 32 - 112 = -80