Answer:
2x^2 + 2x - 83 = 0
Step-by-step explanation:
Consecutive integers differ by 1
Let the first number be x
The next will be (x+1)
The sum of the squares of these two numbers is 85
so we have;
x^2 + (x + 1)^2 =85
= x^2 + x^2 + 2x + 2 = 85
2x^2 + 2x + 2-85 = 0
2x^2 + 2x - 83 = 0
