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Arianaalasgo
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HELP ASAP!!!!! A circle is shown. Secant A D and tangent E D intersect at point D outside of the circle. Secant A D intersects the circle at point B. The length of A B is a, the length of B D is 10, and the length of D E is 12.
Which equation results from applying the secant and tangent segment theorem to the figure?

12(a + 12) = 102
10 + 12 = a2
10(a + 10) = 122
10(12) = a2

HELP ASAP A Circle Is Shown Secant A D And Tangent E D Intersect At Point D Outside Of The Circle Secant A D Intersects The Circle At Point B The Length Of A B class=

Answer :

Loyalitego

Answer:

C)

10(a + 10) = 12 2

Akposevictorgo

Applying the secant-tangent segment theorem, the equation that will result using the figure given is: C. 10(a + 10) = 12².

What is the Secant-tangent Segment Theorem?

The secant-tangent segment theorem states that if a tangent and a secant intersect at a point outside a circle, then the square of the measure of the products of the secant segment and its external secant segment equals the square of the measure of the tangent segment.

Thus, using the figure given, the equation that results from applying the secant-tangent segment theorem would be: C. 10(a + 10) = 12²

Learn more about the secant-tangent segment theorem on:

https://brainly.com/question/26826991

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