What is an equation of the line that passes through the point (-3,-1) and is
perpendicular to the line x - 2y = 62

Answer:
y = -2x - 7
Step-by-step explanation:
x - 2y = 6
-2y = -x + 6
Divide the whole equation by (-2)
[tex]\frac{-2y}{-2}=\frac{-x}{-2}+\frac{6}{-2}\\\\y = \frac{1}{2}x - 3[/tex]
slope = 1/2
Slope of the line perpendicular to this line = -1/m = -1 ÷ (1/2)
[tex]=(-1)*\frac{2}{1}\\\\= -2[/tex]
(-3, - 1)
y -y1 = m(x -x1)
y - [-1] = -2(x - [-3])
y + 1 = -2(x + 3)
y + 1= x* (-2) + 3*(-2)
y + 1 = -2x - 6
y = -2x - 6 - 1
y = -2x - 7