The distance between each pair of parallel lines with the given equation y=3x+12 and y=3x-18 is 30 units
In order to get the required distance, we will first get the y-intercept of each line.
The standard equation of a line is expressed as y = mx + b
m is the slope of the line
b is the y-intercept;
Given the equation y = 3x + 12
Compared with the general equation;
b = 12
Similarly for y = 3x - 18
b = -18
The difference between the y intercept will be the required distance;
d = 12 - (-18)
d = 12 + 18
d = 30 units
Hence the distance between each pair of parallel lines with the given equation y=3x+12 and y=3x-18 is 30 units
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