Answer:
B)[tex]y=\frac{-2}{3}x-\frac{-13}{3}[/tex]
Step-by-step explanation:
2x +3y = 5
3y = -2x + 5
Divide both sides by 3
[tex]\frac{3y}{3}=\frac{-2x}{3}+\frac{5}{3}\\\\y =\frac{-2}{3}x+\frac{5}{3}[/tex]
Parallel lines have same slope.
m = (-2/3) ; (-2 , -3)
y - y1 = m(x -x1)
[tex]y-[-3]=\frac{-2}{3}(x-[-2])\\\\y + 3 = \frac{-2}{3}(x +2)\\\\y + 3 =\frac{-2}{3}x + 2*\frac{-2}{3}\\\\y+3=\frac{-2}{3}x-\frac{4}{3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-3\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{3*3}{1*3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{9}{3}\\\\y=\frac{-2}{3}x-\frac{-13}{3}[/tex]
