Answer :
The length should be 7 while the breadth should be 6 to maximize the area.
Perimeter of the Rectangle
The perimeter of the rectangle is twice the sum of its length and breadth.
[tex]\rm{Perimeter = 2(length +breadth)[/tex]
Area of the rectangle
the area of the rectangle is given as the product of its length and its breadth.
[tex]\rm{Area ={length\times breadth[/tex]
Given to us
Permeter = 26 cm
Perimeter
[tex]\rm{Perimeter = 2(length +breadth)[/tex]
[tex]26 = 2(length +breadth)[/tex]
[tex]13=(length +breadth)[/tex]
Area of the rectangle
As we know that the area is given as the product of length and breadth. so, we need to find those numbers whose sum is 13. while their product gives us the maximum area.
Therefore, for the area to be maximum the length and breadth should be maximum.
[tex]1 \times 12 = 12\\2\times 11 = 22\\3\times 10 = 30\\4\times 9 = 36\\5\times 8 = 40\\6\times 7 = 42[/tex]
Thus, the length should be 7 while the breadth should be 6 to maximize the area.
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