Answer:
8
Step-by-step explanation:
By the property of intersecting tangent and secant outside of a circle.
[tex](4x + 2) \degree = \frac{1}{2} \{(22x + 14) \degree - 122 \degree) \} \\ \\2 (4x + 2) \degree = \{(22x + 14) \degree - 122 \degree) \} \\ \\ (8x + 4) \degree = (22x + 14 - 122) \degree \\ \\ (8x + 4) \degree = (22x - 108) \degree \\ \\8x + 4 = 22x - 108 \\ \\ 4 + 108 = 22x - 8x \\ \\ 112 = 14x \\ \\ x = \frac{112}{14} \\ \\ x = 8[/tex]
