Answer :
Answer:
1. 504.8 g Al(NO3)3
2. 14.3 moles O2
Explanation:
1.
g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3
MM Al(NO3)3 = 212.996 g/mol
2.
moles = mass : molar mass = 456.89: 32 = 14.3 moles O2
Answer:
1. 504.8 g Al(NO3)3
2. 14.3 moles O2
Explanation:
1.
g = moles x molar mass = 2.37 x 212.996 = 504.8 g Al(NO3)3
MM Al(NO3)3 = 212.996 g/mol
2.
moles = mass : molar mass = 456.89: 32 = 14.3 moles O2