Answer:
Surface area of the right triangular prism = 180 m²
Step-by-step explanation:
Surface area of the given right triangular prism = Surface area of triangular sides + Surface area of the rectangular surfaces
Surface area of the triangular sides = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]
= [tex]\frac{1}{2}(AB)(AC)[/tex]
By applying Pythagoras theorem in ΔABC,
BC² = AB² + AC²
(13)² = 5² + (AC)²
AC² = 169 - 25
AC = 12 m
Therefore, area of the triangular sides = [tex]\frac{1}{2}(5)(12)[/tex] = 30 m²
Area of the rectangular side with dimensions 5m × 4m,
= 5 × 4
= 20 m²
Area of the rectangular side with dimensions 13m × 4m
= 13 × 4
= 52 m²
Area of the rectangular side with dimensions 12m × 4m
= 12 × 4
= 48 m²
Total surface area of the prism = 2(30) + 20 + 52 + 48
= 180 m²
