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Write a C++ program to read from the user an integer number of 4 digits and display it in reverse order. For example, if the input is 5723 the output should be 3275. (Hint use / and %). The program should display “Invalid input” if the input value is not a 4 digits number.

Answer :

Answer:

#include <iostream>

using namespace std;

int main() {

 int n, reversedNumber = 0, remainder;

 cout << "Enter a number: ";

 cin >> n;

 int length = to_string(n).length();

 if (length == 4){

   while(n != 0) {

     remainder = n%10;

     reversedNumber = reversedNumber*10 + remainder;

     n /= 10;

   }

   cout << "Reversed Number = " << reversedNumber << endl;

 }

 else{

   cout << "Invalid Input!" << endl;

 }

 return 0;

}

Explanation:

So, it's pretty easy. It finds the remainder to reverse the number and for the invalid input part, you convert the input into a string and then use .length() to find the length. Then you can reverse the number and show whatever output

Answer:

#include <iostream>

using namespace std;

int main() {

int n, reversedNumber = 0, remainder;

cout << "Enter a number: ";

cin >> n;

int length = to_string(n).length();

if (length == 4){

  while(n != 0) {

    remainder = n%10;

    reversedNumber = reversedNumber*10 + remainder;

    n /= 10;

  }

  cout << "Reversed Number = " << reversedNumber << endl;

}

else{

  cout << "Invalid Input!" << endl;

}

return 0;

}

Explanation:

So, it's pretty easy. It finds the remainder to reverse the number and for the invalid input part, you convert the input...

Explanation:

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