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Equilibrium constant Kp for the reaction P4(s) + 6Cl2(g) 4PCl3(l) Kp = 1/ P6Cl2 Kp = P4Cl3/ P6P4 Kp = P4Cl3/ (P6P4) (P6Cl2) Kp = 1/ (P6P4) (P6Cl2)

Answer :

Answer: [tex]K_p=\frac{1}{[p_{Cl_2}]^6}[/tex]

Explanation:

Equilibrium constant is defined as the ratio of pressure of products to the pressuure of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_p[/tex]  

For the given chemical reaction:

[tex]P_4(s)+6Cl_2(g)\rightarrow 4PCl_3(l)[/tex]

The expression for [tex]K_p[/tex] in terms of gaseous is written as:

[tex]K_p=\frac{1}{[p_{Cl_2}]^6}[/tex]

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