Answer :
Answer:
[tex]h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}[/tex]
Step-by-step explanation:
Given: [tex]h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}[/tex]
To find: [tex]h^{-1}(x)[/tex]
Solution:
A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.
Inverse of a function exist if it is both one to one and onto.
[tex]h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}[/tex]
[tex]h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}[/tex]