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Answer :

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Answer:

818.6 KJ/mol

Explanation:

2Al(s) + 3H2O(l) → Al2O3(s) + 3H2(g)

∆H=∆Hp-∆Hr

∆H=(1(∆HAl2O3)+3(∆HH2))-(2(∆HAl)+3(∆HH2O))

∆H=((-1676.0 KJ/mol)+3(0 KJ/mol))-(2(0 KJ/mol)+3(-285.8 KJ/mol))

∆H=-818.6 KJ/mol

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