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A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K.

What is the new pressure of the gas in atmospheres? Answer: 1.47atm

How do I solve this?

Answer :

CintiaSalazargo

Answer:

The new pressure of the gas is 1.47 atm.

Explanation:

STP in chemistry is the abbreviation for standard temperature and pressure. In this case the standard temperature is 273 K (0 ° Celsius or 32 ° Fahrenheit) and the standard pressure is 1 atm of pressure.

The equation that relates P, V, and T is called the ideal gas “law”. This law relates the variables in an initial state 1 and a final state 2 by the expression:

[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]

In this case:

  • P1= 1 atm
  • V1= 32.4 L
  • T1= 273 K
  • P2= ?
  • V2= 28.4 L
  • T2= 352 K

Replacing:

[tex]\frac{1 atm*32.4 L}{273 K} =\frac{P2*28.4 L}{352 K}[/tex]

and solving you get:

[tex]P2=\frac{352 K}{28.4 L} \frac{1 atm*32.4 L}{273 K}[/tex]

P2= 1.47 atm

The new pressure of the gas is 1.47 atm.

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