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1. A sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. If the pressure
of the gas in the 4.0L volume is 210 kPa, what will be the pressure at 2.5L?

Answer :

Serranomarites31go

Answer:

A sample of helium gas in a balloon is compressed from 4.0 L to 2.5 L at a constant temperature. If the pressure of the gas in the 4.0-L volume is 210 kPa, what will the pressure be at 2.5 L? P2 = 340 kPa (336 rounded to 2 s.f.)

Explanation:

sana makatulong

Samueladesida43go

The new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

BOYLE'S LAW:

  • The new pressure of a gas with a change in volume can be calculated by using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question, a sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. The new pressure can be calculated as follows:

  • 210 × 4 = P2 × 2.5

  • 840 = 2.5P2

  • P2 = 840 ÷ 2.5

  • P2 = 336kPa.

  • Therefore, the new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

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