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Answer :

Spacego

Answer:

9 mol H₂O

General Formulas and Concepts:

Math  

Pre-Algebra  

Order of Operations: BPEMDAS  

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry  

Atomic Structure  

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry  

  • Using Dimensional Analysis
  • Analyzing reactions RxN

Explanation:

Step 1: Define

[RxN - Balanced] 6H₂ + O₂ → 3H₂O

[Given] 18 mol H₂

[Solve] mol H₂O

Step 2: Identify Conversions

[RxN] 6 mol H₂ → 3 mol H₂O

Step 3: Stoich

  1. [DA] Set up conversion:                                                                               [tex]\displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})[/tex]
  2. [DA] Simplify:                                                                                                 [tex]\displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})[/tex]
  3. [DA] Divide [Cancel out units]:                                                                     [tex]\displaystyle 9 \ mol \ H_2O[/tex]
Luvadrigo

Answer:

9 mol H₂O

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