Answer:
sinθ = [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²θ + cos²θ = 1 , then
sin²θ + ([tex]\frac{\sqrt{5} }{3}[/tex] )² = 1
sin²θ + [tex]\frac{5}{9}[/tex] = 1
sin²θ = 1 - [tex]\frac{5}{9}[/tex] = [tex]\frac{4}{9}[/tex] ( take the square root of both sides )
sinθ = [tex]\sqrt{\frac{4}{9} }[/tex] = [tex]\frac{2}{3}[/tex]
