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Answer :

The loss in potential energy of the two spheres after the connection is determined as -5.4 x 10¹³ J.

Energy of the spheres before the connection

The potential energy of the spheres before the connections is calculated as follows;

V1 = (kq)/r

V1 = (9 x 10⁹ x 100)/(0.05)

V1 = 1.8 x 10¹³ J

V₂ = (9 x 10⁹ x 50)/(0.01)

V₂ = 4.5 x 10¹³ J

Total energy = (4.5 + 1.8) x 10 10¹³ J = 6.3 x 10¹³ J

  • Total charge of spheres after connection = q₁ + q₂ = 100 c + 50 c = 150 c
  • Radius of the spheres after connection = 15 cm

V =  (9 x 10⁹ x 150)/(0.15)

V = 9 x 10¹²J

Loss in energy

ΔV = 9 x 10¹²J - 6.3 x 10¹³ J

ΔV = -5.4 x 10¹³ J

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