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600.0 mL of a gas is collected at 845.0 mmHg. What will the volume be at standard pressure?


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Answer :

Answer:

667.105ml

Explanation:

V1VP1 / V2P2

V2=V1P1 / P2

Pressure at S.T.P is 760

V2= 600×845/760

V2=667.105ml

Therefore V2 = 667.105ml approximately